How to understand the $ operator in Haskell

You take an (expression)
grab the ) from the right take it to its partner on the left
and pin them together with a |

$ expression

Haskell (#) 

List consumer monad, now with peeking and dropping

Super easy to add peeking. Gosh Haskell is fun to work in

Having to get back into some code I wrote over a year ago

Oof, its mostly good stuff but I need to learn more of what to comment, and what those comments should be

On the bright side I get to play with some type-level reasoning about a protocol, so that is fun!

Beach City

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